DIAGRAM FOR JOINTS SERIES .:: H ::.  

 
example:
Power: 5,5 KW
R.P.M..: 2300
With working angle 10° Factor F=1 we get point P. Torque==23 Nm corresponding to joint size
<D> = 28/29 mm. =Types 05H, 1HB.
With working angle 25° Factor F=0.70 (Kw 5.5 : 0.70 = 7.85 Kw) we get point P1 Torque=33 Nm corresponding to joint size <D> = 32 mm. = Types 1H, 3HB.
Consider that:
Torque in Nm = (9550 x KW) / R.P.M.
  Torque in Nm = (7020 x HP) / R.P.M.
 
N°1 KW = 1.35 HP - N°1 HP = 0.736 KW
  N°1 Kgm= 9.81 Nm - N°1 Nm = 0.102 Kgm