 |
Power: 5,5 KW |
 |
R.P.M..: 2300 |
 |
With working angle 10°
Factor F=1 we get point P. Torque==23 Nm corresponding to joint
size
<D> = 28/29 mm. =Types 05H, 1HB. |
 |
With working angle 25°
Factor F=0.70 (Kw 5.5 : 0.70 = 7.85 Kw) we get point P1 Torque=33
Nm corresponding to joint size <D> = 32 mm. = Types 1H,
3HB. |
|
Consider that: |
|
Torque in Nm = (9550 x KW) / R.P.M. |
| |
Torque in Nm = (7020 x HP) / R.P.M. |
| |
|
|
N°1 KW = 1.35 HP - N°1 HP
= 0.736 KW |
| |
N°1 Kgm= 9.81 Nm - N°1 Nm
= 0.102 Kgm |